Lesson 2 · right-triangle word problems · about 8 minutes · fixes Version 3, questions 5 and 11
The ratios, from Lippman & Rasmussen §5.5:
\[\textbf{S}\text{in}=\frac{\textbf{O}\text{pposite}}{\textbf{H}\text{ypotenuse}}\qquad \textbf{C}\text{os}=\frac{\textbf{A}\text{djacent}}{\textbf{H}\text{ypotenuse}}\qquad \textbf{T}\text{an}=\frac{\textbf{O}\text{pposite}}{\textbf{A}\text{djacent}}\]
A ramp rises to a doorway \(3\) ft high and makes a \(5°\) angle with the ground. How long is the ramp?
\[\sin5°=\frac{3}{L}\]
The unknown \(L\) is on the bottom. Multiply both sides by \(L\), then divide by \(\sin5°\):
\[L\sin5°=3\quad\Rightarrow\quad L=\frac{3}{\sin5°}\]
Sanity check: \(\sin\) of any angle is less than 1, so \(3\sin5°\) is less than 3. A ramp shorter than its own height is impossible, which rules out that answer immediately. (For comparison, the textbook's Example 3 does the same move: \(\sin30°=\frac{7}{b}\Rightarrow b=\frac{7}{\sin30°}=14\).)
A \(20\)-ft ladder makes a \(70°\) angle with the ground. How far is its base from the wall?
\[\cos70°=\frac{d}{20}\]
The unknown \(d\) is on top, so multiply: \(d=20\cos70°\).
The tempting wrong answer is \(20\sin70°\). That's the height up the wall, the side across from the \(70°\) angle, not the side touching it.
Sketch and label each one on paper first. The last question is a review of Lesson 1.